vikram @ 2017.06.27 7:11 AM
Now understand very simply As per video the front load mass is 6 kilogram and the ball mass is 2.5 kilogram.The system height is 15 centimeter from the surface when it is balanced.The ball will work to lift up front load up to 5 centimeter when it will be dropped on the tail of the scale. Now using potential energy formula P.E.=mgh The front load potential energy will be 6*10*.05=3 joule The potential energy of ball will be 2.5*10*.15=3.75 joule it means input is 3.75 joule and output is 3 joule. But the ball is attached with a pulley+generator system which will work to generate energy when ball comes down due to gravity . The ball will generate 3.75 joule energy when it comes down 15 centimeter.but to lift up again this ball there will be need of 3.75 joule energy.now generator works with 80% efficiency then it will be 3 joule but output is also 3 joule .Now if ball is generating 3 joule already itself then a 1 joule input will be sufficient from external source to run the device as output is 3 joule or output will be greater than input. In other words only 1 joule external power will be sufficient to lift up the ball again up to 15 cm or more height. so now actual input will be 1 joule and output will be 3 joule.

angel @ 2017.08.30 7:11 AM
So how can this idea/ experiment be used?